Long time listener, first time caller OK, so I got my X-01 a few weeks ago, plus a 90/75 spinner and 100/75 spinner and the accessory kit. I have since bought an Edge-Pro edge checker to "supplement" my BatGauge. I have played hockey all my life and I am an engineer so I understand ROH and FBV. I recently upgraded the X-10 holder to an X-12 holder (apparently the same as the U-12 holder, but sized for the X-01) but I have not received it yet. I am new to sharpening but I practiced on some used steel and have now sharpened my skates and my 7 year old son's skates several times with the X-01 (90/75 for me and 100/75 for him) and it feels fine to me and he tells me his feel fine. However, what I don't understand are the statements that I have read on here and from Blackstone that you can just leave the pitch wheel alone. Firstly, I don't think it would be there if it didn't have a purpose. And secondly it just doesn't make sense to me. In this picture(click here) in Figure 1 I show a dressed wheel (albeit the apex of the dressing is not at the midline of the wheel, just as would be typical in real life) and a blade that is parallel to the wheel and correctly adjusted for height. This would produce a correctly sharpened blade. Figure 2 shows a parallel blade that is adjusted too high and Figure 3 shows a parallel blade that is adjusted too low. Both of these would produce undesirable results. Now, if I follow the premise that the pitch wheel should be left alone (and let's assume that the toe and heel of the blade are at the same height), then if my state was that of Figure 2, I would adjust both the left and right wheels down by the same amount . I would eventually get to the position shown in Figure 4 where I have "even edges" in that both edges would be the same "height" as read by an edge checker, however, as shown in the picture the "flat" part of the FBV would not be at a right angle to the blade AND the triangles on each side (i.e., the edges) would have different sizes and angles. Can somebody explain to me what I am missing here? I think there needs to be a procedure for getting the blade parallel to the wheel (or perpendicular to the cutting plane of the wheel). Has anyone come up with such a procedure? Thanks -Mike